-36x^2/9-4x+3=0

Solution for -36x^2/9-4x+3=0 equation:

-36x^2/9-4x+3=0

We multiply all the terms by the denominator


-36x^2-4x*9+3*9=0

We add all the numbers together, and all the variables

-36x^2-4x*9+27=0

Wy multiply elements

-36x^2-36x+27=0

a = -36; b = -36; c = +27;
Δ = b2-4ac
Δ = -362-4·(-36)·27
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-72}{2*-36}=\frac{-36}{-72}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+72}{2*-36}=\frac{108}{-72}
=-1+1/2
$